![]() But if you change to remove((Integer)6) (or remove(new Integer (6)) or remove(Integer.valueOf(6)).), at this time, it will belong to the other case.Ä«ut if you know how to reverse the loop, please indicate. So, with your question remove(6) is definitely remove(int index), which means it will delete the element at index is 6. The remaining method is remove(Object o): This is the method when you transmit to the parameter of data types not is int. Regardless of whether in the loop or not. If you want to remove elements from a collection while iterating over it using a for-each loop in Java, you must use an iterator instead of the looping construct. We all know that the safest 'and probably only safe' way of removing an object from a collection while iterating it, is by first retrieving the Iterator, perform a loop and remove when needed Ite. Remove the element at a given index This example will explore E remove (int index): List list new ArrayList<>() list.add('A') list.add('B') list.add('C') list.add('C') list.add('B') list.add('A') (list) String removedStr list. Now, lets see an example of removing elements from ArrayList while looping using for () loop and ArrayList.The first method is remove(int index): This method will be called if you transmit the parameter with data type is int. list.remove() to provide a good example for the scenario, check this. Second, if youre using concurrency, use the CopyOnWriteArrayList and remove the item with. You are right, there are 2 methods remove(x). First, the problem in your code is that you remove the item with your iterator and not by the list. Anyway it turns out - after I ran the code and found out - that it's the former version of remove(x) and so my first impression was correct.Ä«ut I certainly wouldn't expect the second version (backwards) to do that at all. There are two "remove(x)" methods, remember. But then I realized that because you chose Integer as the type of the list entries, I didn't know whether "remove(6)" meant to remove the 7th entry of the list or to remove the first entry containing 6. Usage would be: list1.retainAll (list2) It might not be any more efficient than a naive iteration approach, however, unless you use Set. ![]() Java 8 CollectionremoveIf 2.1 removeIf examples 2.2 removeIf uses Iterator 3. This article shows a few ways to solve it. ![]() In other words, removes from this collection all of its elements that are not contained in the specified collection. In Java, if we remove items from a List while iterating it, it will throw. After all, as soon as i becomes 1 it is never incremented ever again. Retains only the elements in this collection that are contained in the specified collection. But problem is that when the first plan are been deleted, system wont go to other tariff and exiting the for loop. In my case I have 2 tarifs which I need to remove. Paul Clapham wrote:My first impression was that the first version (forward) would remove all of the entries except entry 0. I should to check every tariff and remove it from Plans if type not equals 'L'.
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